Landscaping Math Question?

A landscaper wants to put a uniform border of pine yelp around the outside of a rectangular garden. If the dimensions of the garden are 20 feet by 30 foot, find the width of the pine yelp border of the landscaper has adequate pine bark to cover 336 square foot.

please help me as much as you can, showing as much work as possible, thank you so much!


Answers:    Area of garden = 20' x 30' = 600 sf
Border nouns = 336 sf
Area of garden not covered = 600 sf - 336 sf = 264 sf

So equation for area not covered is:
(20' - 2x) * (30' - 2x) = 264 sf

where on earth x is the width of the border contained by feet.


The above equation results contained by the following quadratic equation:

600 - 100x + 4(x squared) = 264 sf

Subtract 264 sf from both sides results in the following:

336 – 100x + 4(x squared) = 0 sf

Divide both sides by 4:

84 – 25x + (x squared) = 0 sf

Factor:

(21 – x) * (4 – x) = 0 sf

Solve for x:

x = (21, 4)

The singular practical answer is that the border must be 4' wide.
you a short time ago really want to cheat on your math test dont you?
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